Optimal. Leaf size=134 \[ -\frac{\tan ^8(c+d x)}{8 a d}-\frac{5 \tanh ^{-1}(\sin (c+d x))}{128 a d}+\frac{\tan ^5(c+d x) \sec ^3(c+d x)}{8 a d}-\frac{5 \tan ^3(c+d x) \sec ^3(c+d x)}{48 a d}+\frac{5 \tan (c+d x) \sec ^3(c+d x)}{64 a d}-\frac{5 \tan (c+d x) \sec (c+d x)}{128 a d} \]
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Rubi [A] time = 0.236483, antiderivative size = 134, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {2835, 2611, 3768, 3770, 2607, 30} \[ -\frac{\tan ^8(c+d x)}{8 a d}-\frac{5 \tanh ^{-1}(\sin (c+d x))}{128 a d}+\frac{\tan ^5(c+d x) \sec ^3(c+d x)}{8 a d}-\frac{5 \tan ^3(c+d x) \sec ^3(c+d x)}{48 a d}+\frac{5 \tan (c+d x) \sec ^3(c+d x)}{64 a d}-\frac{5 \tan (c+d x) \sec (c+d x)}{128 a d} \]
Antiderivative was successfully verified.
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Rule 2835
Rule 2611
Rule 3768
Rule 3770
Rule 2607
Rule 30
Rubi steps
\begin{align*} \int \frac{\sec (c+d x) \tan ^6(c+d x)}{a+a \sin (c+d x)} \, dx &=\frac{\int \sec ^3(c+d x) \tan ^6(c+d x) \, dx}{a}-\frac{\int \sec ^2(c+d x) \tan ^7(c+d x) \, dx}{a}\\ &=\frac{\sec ^3(c+d x) \tan ^5(c+d x)}{8 a d}-\frac{5 \int \sec ^3(c+d x) \tan ^4(c+d x) \, dx}{8 a}-\frac{\operatorname{Subst}\left (\int x^7 \, dx,x,\tan (c+d x)\right )}{a d}\\ &=-\frac{5 \sec ^3(c+d x) \tan ^3(c+d x)}{48 a d}+\frac{\sec ^3(c+d x) \tan ^5(c+d x)}{8 a d}-\frac{\tan ^8(c+d x)}{8 a d}+\frac{5 \int \sec ^3(c+d x) \tan ^2(c+d x) \, dx}{16 a}\\ &=\frac{5 \sec ^3(c+d x) \tan (c+d x)}{64 a d}-\frac{5 \sec ^3(c+d x) \tan ^3(c+d x)}{48 a d}+\frac{\sec ^3(c+d x) \tan ^5(c+d x)}{8 a d}-\frac{\tan ^8(c+d x)}{8 a d}-\frac{5 \int \sec ^3(c+d x) \, dx}{64 a}\\ &=-\frac{5 \sec (c+d x) \tan (c+d x)}{128 a d}+\frac{5 \sec ^3(c+d x) \tan (c+d x)}{64 a d}-\frac{5 \sec ^3(c+d x) \tan ^3(c+d x)}{48 a d}+\frac{\sec ^3(c+d x) \tan ^5(c+d x)}{8 a d}-\frac{\tan ^8(c+d x)}{8 a d}-\frac{5 \int \sec (c+d x) \, dx}{128 a}\\ &=-\frac{5 \tanh ^{-1}(\sin (c+d x))}{128 a d}-\frac{5 \sec (c+d x) \tan (c+d x)}{128 a d}+\frac{5 \sec ^3(c+d x) \tan (c+d x)}{64 a d}-\frac{5 \sec ^3(c+d x) \tan ^3(c+d x)}{48 a d}+\frac{\sec ^3(c+d x) \tan ^5(c+d x)}{8 a d}-\frac{\tan ^8(c+d x)}{8 a d}\\ \end{align*}
Mathematica [A] time = 0.915934, size = 101, normalized size = 0.75 \[ -\frac{\frac{-15 \sin ^6(c+d x)+177 \sin ^5(c+d x)+104 \sin ^4(c+d x)-184 \sin ^3(c+d x)-129 \sin ^2(c+d x)+63 \sin (c+d x)+48}{(\sin (c+d x)-1)^3 (\sin (c+d x)+1)^4}+15 \tanh ^{-1}(\sin (c+d x))}{384 a d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.091, size = 162, normalized size = 1.2 \begin{align*} -{\frac{1}{96\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{3}}}-{\frac{7}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}-{\frac{15}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) }}+{\frac{5\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) }{256\,da}}-{\frac{1}{64\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}+{\frac{1}{12\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}-{\frac{11}{64\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}+{\frac{5}{32\,da \left ( 1+\sin \left ( dx+c \right ) \right ) }}-{\frac{5\,\ln \left ( 1+\sin \left ( dx+c \right ) \right ) }{256\,da}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.06677, size = 236, normalized size = 1.76 \begin{align*} \frac{\frac{2 \,{\left (15 \, \sin \left (d x + c\right )^{6} - 177 \, \sin \left (d x + c\right )^{5} - 104 \, \sin \left (d x + c\right )^{4} + 184 \, \sin \left (d x + c\right )^{3} + 129 \, \sin \left (d x + c\right )^{2} - 63 \, \sin \left (d x + c\right ) - 48\right )}}{a \sin \left (d x + c\right )^{7} + a \sin \left (d x + c\right )^{6} - 3 \, a \sin \left (d x + c\right )^{5} - 3 \, a \sin \left (d x + c\right )^{4} + 3 \, a \sin \left (d x + c\right )^{3} + 3 \, a \sin \left (d x + c\right )^{2} - a \sin \left (d x + c\right ) - a} - \frac{15 \, \log \left (\sin \left (d x + c\right ) + 1\right )}{a} + \frac{15 \, \log \left (\sin \left (d x + c\right ) - 1\right )}{a}}{768 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.46796, size = 460, normalized size = 3.43 \begin{align*} \frac{30 \, \cos \left (d x + c\right )^{6} + 118 \, \cos \left (d x + c\right )^{4} - 68 \, \cos \left (d x + c\right )^{2} - 15 \,{\left (\cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) + \cos \left (d x + c\right )^{6}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 15 \,{\left (\cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) + \cos \left (d x + c\right )^{6}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (177 \, \cos \left (d x + c\right )^{4} - 170 \, \cos \left (d x + c\right )^{2} + 56\right )} \sin \left (d x + c\right ) + 16}{768 \,{\left (a d \cos \left (d x + c\right )^{6} \sin \left (d x + c\right ) + a d \cos \left (d x + c\right )^{6}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.35526, size = 184, normalized size = 1.37 \begin{align*} -\frac{\frac{60 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} - \frac{60 \, \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a} + \frac{2 \,{\left (55 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )^{2} - 111 \, \sin \left (d x + c\right ) + 57\right )}}{a{\left (\sin \left (d x + c\right ) - 1\right )}^{3}} - \frac{125 \, \sin \left (d x + c\right )^{4} + 980 \, \sin \left (d x + c\right )^{3} + 1662 \, \sin \left (d x + c\right )^{2} + 1140 \, \sin \left (d x + c\right ) + 285}{a{\left (\sin \left (d x + c\right ) + 1\right )}^{4}}}{3072 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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